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Firlakuza [10]
3 years ago
15

A magician performing at children's birthday parties charges $120.00

Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

32 extra goodie bags mark brainlist pls

Step-by-step explanation:

You do 120x4=480

then do 25x3=75

then add 480+75=555

then do 635.00- 555= 80

then do 80 divided by 2.50= 32

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8 0
3 years ago
HELP ASAP WILL GIVE 15 POINTS!!!
sladkih [1.3K]

Answer:

B

Step-by-step explanation:

Since its changing the y, we now it has to be outside the x. So its not A or D. Since it moves up, its a plus. This means its not c, so it has to be B.

5 0
3 years ago
How do you tell if an equation is linear or not????
Tasya [4]
You can tell if the equation is linear or not if the equation makes a straight line on a graph.
3 0
3 years ago
Read 2 more answers
Factor the polynomial by its greatest common monomial factor.
Gwar [14]

Answer: 3b^4(b+5-6b^3)

Step-by-step explanation:

6 0
3 years ago
Please explain how you got your answer!!! The dot plots below show the ages of students belonging to two groups of salsa classes
Rudik [331]

Answer:

Group b most likely has a lower mean age of salsa students

Step-by-step explanation:

Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.

Here we are given with two groups that are Group A and Group B

both having total number of students = 20

Here the mean age of the data is addition of the all ages of different students divided by total number of students.

For group a

total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29

= 15 + 40 + 102 + 96 + 87

=340

The mean age of salsa students= 340 ÷ 20 = 17

For group b

total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21

= 42 + 30 + 56 + 80 + 42

=250

The mean age of salsa students= 250 ÷ 20 = 12.5

So the group b most likely has a lower mean age of salsa students

Learn more about Arithmetic Mean here - brainly.com/question/24688366

#SPJ10

7 0
2 years ago
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