All categories

3 years ago

82 R5 6 ,92 5 4 8 12 12 0

Mathematics

1 answer:

Zarrin [17]3 years ago

4 0

Answer:

see below

Step-by-step explanation:

The first subtraction has a zero result (blue) from the thousands digit, so we know the dividend has 4 in that place. The 5 in the 1s place of the dividend is brought down to fill the space on the bottom line. 6 goes into that number 0 times, so the final quotient digit is 0.

4,925 = 6×820 +5

4,925 ÷ 6 = 820 r5

You might be interested in

[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>

Lana71 [14]

$\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k$
$-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k$

$\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k$
$\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k$

$-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}$
$=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k$
$=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle$

6 0

2 years ago

cfbdhjcfggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

weqwewe [10]

hjkfdshKJhjkhdfkjsahkjhgrkjfdhakjhkjgd sksksksksksks

6 0

2 years ago

Read 2 more answers

Mikayla has $30 in a cafeteria account. She spends $3 each day for lunch. Which equation matches Mikayla's situation?

Reptile [31]

Answer:

y=30-3x

Step-by-step explanation:

5 0

2 years ago

An amusement park is open for 15 hours a day 7 days a week

PilotLPTM [1.2K]

Answer:

f(x)=15 when: 0<x(less than or equal to)3

f(x)=22 when: 3<x<7

f(x)=30 when: 7(is less than or equal to)x

Part B- Evaluate the function for f(2): 15

Step-by-step explanation:

Algebra Nation; Section 8 topic 6

8 0

2 years ago

Very urgent!!!!!

Zinaida [17]

Answer:

number of terms=9

Step-by-step explanation:

$t_{1}=6\\t_{5}=18\\\\t_{n}=t_{1}+(n-1)d\\18=6+(5-1)d\\18-6=4d\\4d=12\\d=12/4=3\\s_{n}=162\\s_{n}=\frac{n}{2}[2t_{1}+(n-1)d]\\162=\frac{n}{2}[2(6)+(n-1)3]\\162 \times 2=n(12+3n-3)\\324=n(3n+9)\\3n^2+9n-324=0\\n^2+3n-108=0\\n^2+12n-9n-108=0\\n(n+12)-9(n+12)=0\\(n+12)(n-9)=0\\n=-12,9\\n=-12 (rejected)$

as number of terms can't be negative.

6 0

2 years ago

Read 2 more answers