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3 years ago

What is 49 to the negative power 1/2?

2 answers:

5 0

So say you have just 49 raised to the 1/2, that is equivocal to the square root of 49, which is 7. Instead, you have 49 raised to the negative half power, so all you need to do is move that term to the denominator of its fraction. You now have 1/49^(1/2) which turns out to be 1/7

marysya [2.9K]3 years ago

3 0

49^-1/2
=1/49^1/2
= 1/Square root of 49
=1/7

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Solve the system of linear equations by substitution.<br><br> y = 2x + 8<br> y = -2x

posledela

Answer:

(- 2, 4 )

Step-by-step explanation:

y = 2x + 8 → (1)

y = - 2x → (2)

substitute y = 2x + 8 into (2)

2x + 8 = - 2x ( add 2x to both sides )

4x + 8 = 0 ( subtract 8 from both sides )

4x = - 8 ( divide both sides by 4 )

x = - 2

substitute x = - 2 into (2)

y = - 2(- 2) = 4

solution is (- 2, 4 )

6 0

3 years ago

Read 2 more answers

the fee for the parking garage at the airport is $16 for the first day plus $4.50 for each additional day. which equation repres

11111nata11111 [884]

It will be a. f=4.5d+16. Unlike the other equations. F represents the fee for the parking garage, and d represents the number of days.

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4 years ago

A public rectangular-shaped pool is 15 m by 30 m. Public pools must be surrounded by a cement

n200080 [17]

Answer:

15m I think

Step-by-step explanation:

Sorry if im wrong

5 0

3 years ago

What requirements must be satisfied? select all that apply.

IrinaK [193]

In order to satisfy the requirement, this are the following that is required;First, at least one observation must be above or below 90 seconds. Second is ether the population is normally distributted or greater than (>) 30, or maybe both.
The answer in this question is A and B.

8 0

3 years ago

Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat

NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that $n = 65, \pi = 0.76$

99% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964$

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

6 0

3 years ago