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3 years ago

14

Given this is an odd number function, which of the following are equal to O(9)

1 answer:

Bumek [7]3 years ago

7 0

It is 9 because I think It is equaltion to 9

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Sawsan recorded the favorite sport of students at her school. She surveyed 200 students. How many students chose tennis?

deff fn [24]

20 students.
10% chose tennis, and .10(200)=20

6 0

3 years ago

State if the polygons are similar

creativ13 [48]

No these polygons are not similar or equal

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2 years ago

Suppose that two cards are randomly selected from a standard 52-card deck. (a) What is the probability that the first card is

ser-zykov [4K]

Answer:

(a) $\frac{1}{17}$ (b) $\frac{1}{16}$

Step-by-step explanation:

GIVEN: Suppose that two cards are randomly selected from a standard $52$ card deck.

TO FIND: (a) What is the probability that the first card is a club and the second card is a club if the sampling is done without replacement? (b) What is the probability that the first card is a club and the second card is a club if the sampling is done with replacement.

SOLUTION:

(a)

Probability that first card is club $P(A)=\frac{\text{total club cards}}{\text{total cards}}$

$=\frac{13}{52}$

$=\frac{1}{4}$

As sampling is done without replacement.

probability that second card is club $P(B)=\frac{\text{total club cards}}{\text{total cards}}$

$=\frac{12}{51}$

$=\frac{4}{17}$

Probability that first card is club and second card is club $=P(A)\times P(B)$

$=\frac{1}{4}\times\frac{4}{17}=\frac{1}{17}$

(b)

Probability that first card is club $P(A)=\frac{\text{total club cards}}{\text{total cards}}$

$=\frac{13}{52}$

$=\frac{1}{4}$

As sampling is done with replacement.

probability that second card is club $P(B)=\frac{\text{total club cards}}{\text{total cards}}$

$=\frac{13}{52}$

$=\frac{1}{4}$

Probability that first card is club and second card is club $=P(A)\times P(B)$

$=\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}$

3 0

3 years ago

Py+7=6y+qp, y, plus, 7, equals, 6, y, plus, q y=y=y, equals

Archy [21]

Py +7 = 6y + qp

Solve the equation for y

To solve the equation for y we need to get y alone

Py +7 = 6y + qp

Subtract 6y from both sides

Py - 6y +7 = + qp

Subtract 7 from both sides

Py - 6y = + qp - 7

Now factor out y

(P - 6)y = qp - 7

Divide by P - 6 from both sides

$y =\frac{qp - 7}{(P - 6)}$

6 0

3 years ago

Read 2 more answers

Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ag

ivanzaharov [21]

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

$D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

$D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

$D=2((7)-1+(D-16)-1)+1$

$D=2(6+D-15)+1$

$D=2(D-9)+1$

$D=2D-18+1$

$D=17 Years$

Dave is 17 years old

Therefore

Johns age is

$J'=(D-16)$

$J'=17-16$

$J'=1year old$

John is 1 year old

7 0

2 years ago