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3 years ago

Factorise : (a+b)^2+4(a+b)+4

Mathematics

1 answer:

harina [27]3 years ago

4 0

Answer:

2(3+2a+2b)

Step-by-step explanation:

6+4(a+b)

2(3+2(a+b))

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baye's theorem certain test for cholera gives 5% false positives, and 12% false negatives. If the test gives correct results 93%

jekas [21]

Answer:

The percentage of people having cholera is 89.19%.

Step-by-step explanation:

According to the Bayes' theorem the total probability of <em>A</em> is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

Let <em>X</em> = a person has chorea and <em>Y</em> = the test is positive.

Given:

$P(X^{c}|Y)=0.05\\P(X|Y^{c})=0.12\\P(Y)=0.93$

The value of $P(X|Y)$ is:

$P(X|Y)=1-P(X^{c}|Y)=1-0.05=0.95$

Compute the value of P (X) as follows:

$P(X)=P(X|Y)P(Y)+P(X|Y^{c})P(Y^{c})\\=(0.95\times0.93)+(0.12\times(1-0.93))\\=0.8835+0.0084\\=0.8919$

The percentage of people suffering form cholera is, 0.8919 × 100 = 89.19%.

Thus, the percentage of people having cholera is 89.19%.

3 0

3 years ago

Sandra graphed the system of equations that can be used to solve x^3-2x^2-11x+12=x^3-13x-12 What are the roots of the polynomial

inn [45]

Answer: C.) –3, 4.

Step-by-step explanation: Given equation $x^3-2x^2-11x+12=x^3-13x-12$ .

Subtracting x^3 from both sides, we get

$x^3-x^3-2x^2-11x+12=x^3-x^3-13x-12$ .

$-2x^2-11x+12=-13x-12$ .

Adding 13x and 12 on both sides, we get

$-2x^2-11x+12+13x+12=-13x-12+13x+12$ .

$-2x^2+2x+24=0$ .

Dividing whole equation by -2, we get

$x^2-x-12=0$ .

Factoring quadratic, we get

$(x-4)(x+3)=0$ .

x-4=0 and x+3=0

7 0

4 years ago

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(3-1) + (1 - 2) =<br> what is the answer to this question? i don’t understand it.

Ganezh [65]

Answer:

Step-by-step explanation:

$(3 - 1) + (1 - 2)$

Order of operations is () ^ * / + -

$2 + ( - 1)$

$2 - 1$

$1$

6 0

3 years ago

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I need to solve for x

yan [13]

Answer:

88°

Step-by-step explanation:

a line is equal to 180

180-92=88

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4 years ago

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9 x 5<br> -<br> 9 im give brainlists

Alenkinab [10]

Answer:

9 x 5 - 9 = 36

Step-by-step explanation:

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3 years ago

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