Hi there!
![\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29%20%7D)
We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):
Taking the derivative gets:
Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):
0 = -8/x³ - 2
2 = -8/x³
2x³ = -8
x³ = -4
![x = \sqrt[3]{-4}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B-4%7D)
Another critical point is also where the graph has an asymptote (undefined), so at x = 0.
Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:
f'(1) = -8/1 - 2 = -10 < 0
f'(-1) = -8/(-1) - 2 = 6 > 0
f'(-2) = -8/-8 - 2 = -1 < 0
Thus, the values of x are:
![(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20%5Csqrt%5B3%5D%7B-4%7D%29%20%5Ctext%7B%20and%20%7D%20%280%2C%20%5Cinfty%29)
Answer:
400
Step-by-step explanation:
12000 X 60%=7200-parents
12000-7200=4800-owen
4800/12=400 is what owen will save monthly
Answer:
<em><u>Linear function :</u></em>The characteristic property of linear functions is that when the input variable is changed, the change in the output is proportional to the change in the input. Linear functions are related to linear equations.
Step-by-step explanation:
We have
y=mx+c
for 1st
not satisfied.
for
2nd
not satisfied
<em><u>3rd</u></em>
<em><u>3rd satisfied</u></em>
4th
[note : substitute value of x to get value of y from table]
so
<u>t</u><u>h</u><u>i</u><u>r</u><u>d</u><u> </u><u>table represents a linear function.</u>
Answer:
Yes
Step-by-step explanation:
A function is a relation where each input has only one output
The table shown follows this, each input has only one output, therefore it is a function.
