The value of the quadratic equation evaluated at 0 is equal to 1.
<h3>How to evaluate a quadratic equation at a given x-value</h3>
In this question we have a quadratic equation and we need to evaluate the function at x = 0 and find the result by algebraic procedures. Now we proceed to evaluate the function:
g(x) = - 2 · x² + 1, x = 0 Given
g(0) = - 2 · 0² + 1 Previous step
g(0) = - 2 · 0 + 1 Cancellative theorem
g(0) = 0 + 1 Cancellative theorem
g(0) = 1 + 0 Commutative property
g(0) = 1 Modulative property / Result
The value of the quadratic equation evaluated at 0 is equal to 1.
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Answer:
The graph attached below is for r=2+ 2sin θ where θ=pi
Step-by-step explanation
The coordinates in a polar equation are written as (r,θ)
r= radius and θ is the angle
⇒⇒⇒ so this mean we rotate θ radians and of the size r units
In our case assume θ= where 0≤θ≤2
Answer: 180 – given angles
Step-by-step explanation: summing up all the angles should be 180° hence and the angles given and subtract it from 180 to get the unknown angle
14430
13,000 x 1.11 (111%) = 14430
Answer: Chillin hbu?
Step-by-step explanation: