A decline in the real GDP that occurs for at least two or more quarters is called a depression. The correct option among all the options that are given in the question is option "b". There is a very thin line of difference between recession and depression. when the real GDP falls for a repeated number of periods, then it is depression.
Answer:
$360
Explanation:
Interest Expense associated with the loan is the only operating cash flow. We need to calculate the interest expense first
As the note is issued on August 1, year 1, only 5 months has been passed on December 31, year 1, So we calculate the interest expense for only 5 months.
Interest Expense = Value of Note x Stated Interest rate x 5/12 = $10,800 x 8% x 5/12 = $360
It is assumed that the interest is paid on December 31, year 1.
Answer:
new net worth = 79.2 billion
Explanation:
given data
net worth = $76.0 billion
gains = $3.20 billion
to get here
new net worth
solution
we get here new net worth that is express as
new net worth = net worth + gains .............................1
put here value and we will get here
new net worth = $76.0 billion + $3.20 billion
new net worth = 79.2 billion
Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:

Restrictions:
- High-grade ore: 
- Medium-grade ore: 
- Low-grade ore: 
- No negative hours: 
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.