Question

A large diamond with a mass of 4289.6 grams was recently discovered in a mine. If the density of the diamond is 3.51 grams over centimeters cubed, what is the volume? Round your answer to the nearest hundredth.
142.78 cm3

384.96 cm3

1221.9 cm3

33759.15 cm3

Answer 1

There are several information's already given in the question. Based on those information's the answer can be deduced.
Mass of the diamond = 4289.6 grams
Density of the diamond = 3.51 gm/cm^3
Then
Volume of the diamond = 4289.6/3.51
                                      = 1221.9 cm^3
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the third option or the penultimate option.

Answer 2

Answer: $1222.11\ cm^3$

Step-by-step explanation:

Given: The mass of a large diamond = 4289.6 grams

The density of the diamond = 3.51 $\text{ grams/ }cm^3$

We know that the formula to calculate density is given by :-

$\text{Density}=\dfrac{\text{Mass}}{\text{ Volume}}\\\\\Rightarrow\text{Volume}=\dfrac{\text{Mass}}{\text{Density}}$

$\Rightarrow\text{Volume}=\dfrac{4289.6}{3.51}=1222.10826211\approx1222.11\ cm^3$