Answer: i) 1 - 9x² - 12x
ii) 17 - 3x²
iii) - 20 + 10x² - x⁴
<u>Step-by-step explanation:</u>
g(x) = 3x + 2 h(x) = 5 - x²
i) h(g(x))
h(3x + 2) = 5 - (3x + 2)²
= 5 - (9x² + 12x + 4)
= 5 - 9x² - 12x - 4
= 1 - 9x² - 12x
ii) g(h(x))
g(5 - x²) = 3(5 - x²) + 2
= 15 - 3x² + 2
= 17 - 3x²
iii) h(h(x))
h(5 - x²) = 5 - (5 - x²)²
= 5 - (25 - 10x² + x⁴)
= 5 - 25 + 10x² - x⁴
= -20 + 10x² - x⁴
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.
You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
Answer:
ill try
Step-by-step explanation:
Factor and group common ones
60=2*2*3*5*x*x*x*x*y*y*y*y*y*y*y
45x^5^5=3*3*5*x*x*x*x*x*y*y*y*y*y
75x^3y=3*5*5*x*x*x*y
the commmon gropu to all is 3*5*x*x*x*y=15x^3y
