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slamgirl [31]
3 years ago
11

list the two dimensions of two different rectangular prisms in which each has a volume of 6600 cubic centimeters answers

Mathematics
2 answers:
Dafna1 [17]3 years ago
4 0
Give more detail to you question
Svetach [21]3 years ago
3 0
Square i think? And i dont know the other one.
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A BOOKMARK
Angelina_Jolie [31]

Answer:

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8 0
3 years ago
Precalculus. Please look at the picture
erik [133]

Answer:

<u>Exponential model</u>

y=Ae^{rt}

where:

  • y = value at "t" time
  • A = initial value
  • r = rate of growth/decay
  • t = time (in years)

<h3><u>Part (a)</u></h3>

Given:

  • y = 100 g
  • t = 0 years

Substituting given values into the formula and solving for A:

\begin{aligned}y & =Ae^{rt}\\\implies 100 & = Ae^{r \times 0}\\100 & = Ae^0\\100 & = A(1)\\A & = 100\end{aligned}

<h3><u>Part (b)</u></h3>

Given:

  • A = 100 g
  • y = 50 g when t = 30.17

Substituting the given values into the equation and solving for r:

\begin{aligned}y& =Ae^{rt}\\\\\implies 50 & =100e^{30.17r}\\\\\dfrac{1}{2} & = e^{30.17r}\\\\ln \dfrac{1}{2} & = \ln e^{30.17r}\\\\\ln 1-\ln2 & =30.17r \ln e\\\\0-\ln 2 & =30.17r(1)\\\\-\ln 2 & =30.17r\\\\r & = \dfrac{-\ln 2}{30.17}\end{aligned}

Therefore, the final equation is:

y=100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}

<h3><u>Question 1</u></h3>

<u>Part (a)</u>

Q:   From 100g how much remains in 80 years?

\begin{aligned}t=80 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)80}\\& = 15.91389949 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:  How long will it take to have 10% remaining?

10% of 100 g = 10 g

\begin{aligned}y=10 \implies 10 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{10} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{10} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 10}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 100.2225706\: \sf years\end{aligned}

<h3><u>Question 2</u></h3>

<u>Part (a)</u>

Q:   How much remains after 50 years (time)?

<u></u>

\begin{aligned}t=50 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)50}\\& = 31.70373153 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:   How long to reach 20 g (amount remaining)?

<u></u>\begin{aligned}y=20 \implies 20 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{5} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{5} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 5}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 70.05257062\: \sf years\end{aligned}

3 0
2 years ago
18.96 x 2.03 correct to 2 significant figures equals what?
Andreas93 [3]

9514 1404 393

Answer:

  38

Step-by-step explanation:

The product of the given numbers is 38.4888. Rounding this to two significant digits gets you 38.

6 0
3 years ago
2
Stolb23 [73]

Answer:

Chord 12 cm long subtends an angle of 40 degrees at the center of a circle.

θ= 40° = 0.698 rad

Let R be the radius of circle.

Chord Length = 2Rsin(θ/2)

12=2R sin (0.698 /2)

R= 17.54

Ans: Radius of circle = 17.54 cm

8 0
3 years ago
The triangle shown below has an area of 16 units squared
pashok25 [27]
The area of the triangle is 16 un squared
6 0
3 years ago
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