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4 years ago

10

Choose the correct simpification of (5x^2y^3z^4)(6x^3y^4z^2)

1 answer:

VladimirAG [237]4 years ago

5 0

Answer:

$30x^5y^7z^6$

Step-by-step explanation:

$\left(5x^2y^3z^4\right)\left(6x^3y^4z^2\right)$

$5x^2y^3z^4\cdot \:6x^3y^4z^2$

$30x^3x^2y^4y^3z^4z^2$

$30x^5y^4y^3z^4z^2$

$30x^5y^7z^4z^2$

$30x^5y^7z^6$

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< J and < M are base angles of isosceles trapezoid JKLM. If measure < J = 20x +9 and m < M= 14x +15, find measure &l

Kazeer [188]

The base angles of an isosceles trapezoid are equal. Therefore:
20x + 9 = 14x + 15
6x = 6
x = 1
So, the base angles both equal 29 degrees.
In a trapezoid, the sum of the angles attached to the same leg always = 180 degrees.
Therefore, angle K and angle L equal 151 degrees.

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3 years ago

Fifty-two more than a number is -11

Zanzabum

Answer:

-63

Step-by-step explanation:

-63 plus 52 is-11. have a good day

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2 years ago

What is the birthday polynomial for 10/1/2006

zubka84 [21]

Answer:

Simplified version: 10x^5 - 1x^4 + 2x^3 - 6

Step-by-step explanation:

Since your birthday is 10/1/2006 we can use 1012006 as our digits.

We can make a random polynomial: 10x^5 - 1x^4 + 2x^3 + 0 x^2 + 0x - 6

(since 0 are meaningless we can simply this further into the below equation)

10x^5 - 1x^4 + 2x^3 - 6

Here's an example: https://www.wyzant.com/resources/answers/730225/birthday-polynomial-project-for-04-15-2004

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2 years ago

The director of the library believes that 14% of the library's collection is checked out. If the director is right, what is the

Ksivusya [100]

Answer: 0.2643

Step-by-step explanation:

Let p be the population proportion and $\hat{p}$ be the sample proportion .

As per given question , we have

$p=0.14\\\\ \hat{p}=0.13\\\\ n=478$

z-score : $\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$z=\dfrac{0.13-0.14}{\sqrt{\dfrac{0.14(1-0.14)}{478}}}\\\\=-0.630087269176\approx-0.63$

The required probability ( using z-table ):-

$P(z$

Hence, the probability that the proportion of books checked out in a sample of 478 books would be less than 13% = 0.2643

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4 years ago

Determine whether the function below is an even function, an odd function, both, or neither. f(x)=x^2+3 Answers choices: A. Odd

liraira [26]

The answer is: B. Even function.

The explanation for this exercise is shown below:

1. You must substitute $x$ with $-x$ in the function:

$f(x)=x^{2} +3\\ f(-x)=(-x)^{2} +3\\ f(-x)=x^{2} +3$

2. As you can see, $f(-x)=f(x)$ , therefore it is an Even function.

8 0

4 years ago

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