Answer:
the answer is 8.55 or 8 and 11/20
y = - 
(x - 5)² + 4
the equation of a quadratic in standard form is
y = a(x - h)² + k ( where (h , k ) are the coordinates of the vertex and a is a multiplier )
given vertex = ( 5, 4 ) then
y = a(x - 5)² + 4 ( to find a substitute (7 , 1 ) into the equation )
1= 4a + 4
4a = - 3 ⇒ a = -
y = - (x - 5)² + 4 ← ( in vertex form )
It would be x= -4/7......
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
Answer:
Slope- 5 y-int- (0,0)
Step-by-step explanation:
y=mx+b, where m=slope and b=y-int. m=5, and we don't see a b, so it must be 0.
