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3 years ago

What is a Ratio ??????

Mathematics

2 answers:

vfiekz [6]3 years ago

6 0

It's easy to look it up in your phone

777dan777 [17]3 years ago

6 0

Noun
the quantitative relation between two amounts showing the number of times one value contains or is contained within the other.
"the ratio of men's jobs to women's is 8 to 1"
synonyms: proportion, comparative number, correlation, relationship, correspondence; More
the relative value of silver and gold in a bimetallic system of currency.

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B) Write an expression for fin terms of d.<br> c) Work out e-f<br> Simplify your answer.

olga2289 [7]

Answer:

3d+ e+f

Step-by-step explanation:

7 0

3 years ago

AREA OF A CIRCLE<br> r=3 cm

statuscvo [17]

28.27 is the area bc i had this as an example before lol

5 0

2 years ago

I’m really confused somebody please help

Nady [450]

Answer: The mechanic worked for 4.25 hours for the fourth customer.

First find out the slope.
Y^2-y^1/x^2-x^1
210-90/3-1=60

Slope: 60

Then find out what the y-intercept is by plugging in values we know into y=mx+b

90=60(1)+b
30=b

Y=60x+30

Substitute the y with 285 to find out the x (hours)

285=60x+30
4.25=x

5 0

3 years ago

What is the slope of y=-1+3xy=−1+3xy, equals, minus, 1, plus, 3, x?

kari74 [83]

Answer:

Step-by-step explanation:

Given the function: y=-1+3x

$Slope=\dfrac{\text{Change in y axis}}{\text{Change in x axis}}$

The above is the derivative of y with respect to x.

Therefore, for

$y=-1+3x\\\dfrac{dy}{dx}=3$

Therefore the slope of the function is 3.

6 0

3 years ago

Read 2 more answers

Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.

ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region $\mathcal T$ by computing the double integral of the density function over $\mathcal T$ :

$\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy$

The boundary of $\mathcal T$ is determined by a set of lines in the $x,y$ plane. One way to describe the region $\mathcal T$ is by the set of points,

$\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}$

So the mass is

$\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx$

$=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52$

6 0

3 years ago