To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) =
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
Answer:
y = −3x+7
Step-by-step explanation:
m = slope
slope = change in y / change in x
slope = ▲y/▲x
slope = -3 / 1
slope = -3
y-intersect = (0,7)
The slope-intercept form of linear equation:-
y = mx + b
where:
m = the slope
b = y-intersect
*we plot the information we have get in the formula
y = mx + b
y = -3x + 7
*and this is the equation of the graph
Answer: Choice D
Explanation:
The range is the set of all possible y outputs of a function. The highest y can go is y = 1, which occurs at the vertex. We can have y = 1 or y be smaller than this. Therefore, the range is 
Pt 1 - how much the value goes down each year
Pt 2 - how much the car was originally worth
The perimeter without the diagonal is 4*120 = 480
That covers the outside of the field
The diagonal is 120 *

= 169.7 yd
480 + 169.7 = 649.7 yd total of fencing