Answer:
$300
Step-by-step explanation:
Let x represent the side length of the square base in feet. Then the height of each side is ...
... h = (50 ft³)/(x ft)² = (50/x²) ft
The cost of the sides of the box is then ...
... (4 sides) × (x ft)(50/x² ft)/side × $2/ft² = $400/x
The cost of the bottom is ...
... (x ft)² × $25/ft² = $25x²
So, the total dollar cost is
... C = 400/x + 25x²
This will be a minimum where its derivative with respect to x is zero.
... 0 = -400/x² +50x
... 400/50 = 8 = x³ . . . . . add 400/x²; multiply by x²/50
... x = ∛8 = 2
For this value of x, the minimum cost is ...
... C = 400/2 + 25·2² = 300
The minimum possible cost is $300.
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<em>Comments on the problem</em>
1) Cardboard boxes are usually made of cardboard. They are rarely made of wood and alumninum.
2) The cost of the bottom is half the cost of the sides. When the dimensions are unconstrained, you will find (as here) the cost is shared equally between the bottom and pairs of opposite sides—each being 1/3 the total cost.
