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Serjik [45]
3 years ago
7

The graph of g(x) is obtained by reflecting the graph of f(x)=2|x| over the x-axis.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0
Answer: Choice C) 
g(x) = -|2x|

You get this answer by simply sticking a negative out front of the original function. In other words, g(x) = -f(x) or more technically, g(x) = -1*f(x).

The negative will flip every y coordinate from positive to negative (or vice versa)

You'll also use the idea that |2x| = 2|x|. The two can be pulled out since we can say |x*y| = |x|*|y|
So |2*x| = |2|*|x| = 2|x|

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The surface area of this prism is _______ cm squared
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Can you help me with my posted questions
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Feliz [49]

Answer:

PRT%

Step-by-step explanation:

<em>PR</em><em>T</em>

<em>= 320 \times 2.3 \times 20 \div 100 = 1472</em>

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2 years ago
Which angle is an vertical angle with angle BCA. <br><br> Need help with this question please
vlada-n [284]

Answer:

Angle 2

Step-by-step explanation:

<u><em>Vertical angles are congruent opposite angles when two lines intersect.
Line E A and B N intersect each other to form Angles B C A and E C N, or angle C and angle 2, which are congruent to each other as well, which makes them vertical to each other.</em></u>

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2 years ago
How do you solve this equation? 2 1/2 - 3/4
borishaifa [10]

Answer:

1 3/4

Step-by-step explanation:

you have to convert the mixed numbers into improper fractions first

2 1/2 turns into 5/2

then you make the denominators the same

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then you subtract

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4 0
2 years ago
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.
vova2212 [387]

Answer:

▢ $\overline{DG}$ ≅ $\overline{FG}$

▢ $\overline{DG}$ ≅ $\overline{BG}$

▢ $\overline{GE}$ bisects \displaystyle ∠DEF

▢ $\overline{GA}$ bisects \displaystyle ∠BAF

Step-by-step explanation:

As you can see, angles \displaystyle BAF and \displaystyle DEF form two half-kites, which you should know have <em>two</em><em> </em><em>pairs of</em><em> </em><em>congruent</em><em> </em><em>sides</em>, therefore segments \displaystyle GA and \displaystyle GE are what you call angle bisectours, which is why segments \displaystyle FG, \displaystyle DG, and \displaystyle BG are congruent.

I am joyous to assist you at any time.

4 0
3 years ago
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