The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
<u />
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be



= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
12.95 30
-------- = ----
x 100
1295 = 30x
------- -----
30 30
x = 43.16666667
not sure how u want to round
Answer:
The function has a domain of all real numbers.
The function has a range of {y|–∞ < y <∞ }.
The function is a reflection of y=∛x
Step-by-step explanation:
Given:
f(x)=-∛x
domain is set of all values that x can take for which the function is defined, so
for above function domain= set of all real numbers
range is set of values that corresponds to the set of values of domain, so for given f(x) range={y|–∞ < y <∞ } set of real numbers
Now f(x)=-∛x hence its reflection will be
-f(x)=-(-∛x)
y=∛x !
Set



so that the volume element is

The integral is then


and so evaluates to 0.
Answer:
Where is the graph?
Step-by-step explanation: