Area of a cirlce=πr²
we have two radius:2r and r
area of the cirlce₁ + area of the circle₂=80 m²
area of the circle₁=π(2r)²
area of the circle₂=πr²
Then, we can suggest this quation:
π(2r)²+πr²=80
4πr²+πr²=80
π(4r²+r²)=80
π(5r²)=80
5πr²=80
r²=80/5π
r=√(80/5π)≈2.26
radius of the largest cirlce=2r=2(2.26)=4.51
Answer: the radius of the largest circle is 4.51 m
Answer:
The area of the trapezoid is 
Step-by-step explanation:
we know that
The area of a isosceles trapezoid is equal to the area of two isosceles right triangles plus the area of a rectangle
step 1
<em>Find the area of the isosceles right triangle</em>
Remember that
In a isosceles right triangle the height is equal to the base of the triangle
we have
so
The area is equal to
substitute the values
step 2
Find the area of the rectangle
The area of the rectangle is equal to
we have
-----> is the height of the trapezoid
-----> the diagonal of the rectangle
Applying the Pythagoras Theorem
The area of the rectangle is
step 3
Find the area of the trapezoid
The directrix of a parabola<span> is the horizontal line found by subtracting p p from the y-coordinate k k of the vertex if the </span>parabola<span> opens up or down. Substitute the known values of p p and k k into the formula and simplify. Use the </span>properties<span> of the </span>parabola<span> to analyze and graph the </span>parabola<span>.</span>
Domain is the set of numbers you can use for the equaiton
remember you can't divide by zero, or take the squaer root of a negtive number (we don't have sqrts in this quesiton so don't worry about last one)
so you can't divide by 0
domain =all real number except those that make divide by zero
where is that?
x-1=0
x=1
when x=1, we can't allw that
domain=all real numbers except 1
