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zmey [24]
4 years ago
9

How do I find the properties of a parabola

Mathematics
1 answer:
Elanso [62]4 years ago
3 0
The directrix of a parabola<span> is the horizontal line found by subtracting p p from the y-coordinate k k of the vertex if the </span>parabola<span> opens up or down. Substitute the known values of p p and k k into the formula and simplify. Use the </span>properties<span> of the </span>parabola<span> to analyze and graph the </span>parabola<span>.</span>
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A shop sells candles in boxes of 3 for $12.60 each or 1 candle for $5.50. How many candles can Julia buy with $20?
kherson [118]

Answer: the number of scented candles ... x

the number of unscented candles ... y

x + y = 28

$16 * x + $10 * y = $400  ... 16 * x + 10 * y = 400

Step-by-step explanation: This is the equation

16 * (28 - y) + 10 * y = 40016 * 28 - 16 * y + 10 * y = 400448 - 400 = 16 * y - 10 * y48 = 6 * y    /6y = 48 / 6y = 8x = 28 - y = 28 - 8 = 20Result: The candle shop sold 20 scented candles and 8 unscented candles today.

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4 0
4 years ago
What number can you add to π to get a rational number?
Sergio039 [100]
-pi. this one was asked very recently
7 0
4 years ago
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If a is real and the product of (a+6i)(5-3i) is a real number, the find a.
irina [24]

Answer:

5a−3ai+30i+18

Step-by-step explanation:

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3 0
2 years ago
Say a business found that 98.3% of soda cans at a production facility in California are filled correctly. The company chooses 10
Shtirlitz [24]

Answer:

The events must be independent.

Step-by-step explanation:

The only assumption that must be made is that the events are independent. That is, the amount of soda in a given can does not depend on the amount of soda of any previous can filled at the same facility.

If this assumption holds, then the probability of finding exactly k cans of soda filled correctly would be

\displaystyle\binom{100}{k}(0.983)^k(1-0.983)^{100-k}

where

\displaystyle\binom{100}{k}=\displaystyle\frac{100!}{k!(n-k)!}

are combinations of 100 elements taken k at a time.

3 0
4 years ago
Please help ASAP. The question is down below.
erastovalidia [21]

Answer:

(a) and (a)

Step-by-step explanation:

In both questions the denominator of the rational functions cannot be zero as this would make them undefined. Equating the denominators to zero and solving gives the values that x cannot be.

Given

\frac{x-3}{(3-x)(2+x)}

solve (3 - x)(2 + x) = 0

Equate each factor to zero and solve for x

3 - x = 0 ⇒ x = 3

2 + x = 0 ⇒ x = - 2

x = 3 and x = - 2 are excluded values → (a)

------------------------------------------------------------------------

Given

\frac{-9x+3}{6x^2+10x-4}

solve

6x² + 10x - 4 = 0 ← in standard form

(x+ 2)(6x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

6x - 2 = 0 ⇒ 6x = 2 ⇒ x = \frac{1}{3}

x = \frac{1}{3} and x = - 2 are excluded values → (a)

7 0
3 years ago
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