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Kitty [74]
3 years ago
15

How do I find the domain?

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0
Domain is the set of numbers you can use for the equaiton

remember you can't divide by zero, or take the squaer root of a negtive number (we don't have sqrts in this quesiton so don't worry about last one)

so you can't divide by 0
domain =all real number except those that make divide by zero

where is that?
x-1=0
x=1

when x=1, we can't allw that

domain=all real numbers except 1
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Step-by-step explanation:

(300-60)/6,4=37,5

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A college basketball game is 40 minutes long. Derrick’s favorite player participated for 60% of last week’s game. How many minut
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The sphere is _____ cubic centimeters bigger than the cube. (Round to the nearest cubic centimeter.)
Misha Larkins [42]

ANSWER

The sphere is 10762 cubic centimeters bigger than the cube.

EXPLANATION

We want to find the difference in the volumes of the sphere and the cube.

To do this, we have to find the volumes of the sphere and cube and subtract that of the cube from the sphere.

The volume of a sphere is given as:

V=\frac{4}{3}\pi r^3

where r = radius

The radius of the sphere is 15 centimeters. Therefore, the volume of the sphere is:

\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot15^3 \\ V\approx14137\operatorname{cm}^3 \end{gathered}

The volume of a cube is given as:

V=s^3

where s = length of the side

The length of the side of the cube is 15 centimeters. Therefore, the volume of the cube is:

\begin{gathered} V=15^3 \\ V=3375\operatorname{cm}^3 \end{gathered}

Therefore, the difference in the volumes of the sphere and cube is:

\begin{gathered} V_d=V_s-V_c \\ V_d=14137-3375 \\ V_d=10762\operatorname{cm}^3 \end{gathered}

Therefore, the sphere is 10762 cubic centimeters bigger than the cube.

6 0
1 year ago
Consider the quadratic equation 3x^2-6=2x. (a) What is the value of the discriminant? (b) What does the discriminant of the quad
aleksley [76]

Answer:

(a) discriminant is positive, 76

(b) the above tells you there are two real roots

Step-by-step explanation:

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5 0
3 years ago
Let f(x)=x^3-x-1
alexira [117]
f(x) = x^3 - x - 1

To find the gradient of the tangent, we must first differentiate the function.

f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1

The gradient at x = 0 is given by evaluating f'(0).

f'(0) = 3(0)^2 - 1 = -1

The derivative of the function at this point is negative, which tells us <em>the function is decreasing at that point</em>.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

y = -x + c

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

f(0) = (0)^3 - (0) - 1 = -1

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}
6 0
3 years ago
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