Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,

Length of the arc = radius x θ = 8 x 45 x π/180
= 8 x π/4 = 2π = 6.28 in ~ 6.3 in
9514 1404 393
Answer:
(c) Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Step-by-step explanation:
Try the numbers in the constraints to see if they work.
<u>Build hours</u>:
(4 h/child bike)(10 child bikes) = 40 hours
(6 h/adult bike)(12 adult bikes) = 72 hours
total build hours: 40 +72 = 112, less than 120; constraint is met
<u>Test hours</u>:
(4 h/child bike)(10 child bikes) = 40 hours
(4 h/adult bike)(12 adult bikes) = 48 hours
total test hours: 40 +48 = 88, less than 100; constraint is met
__
Both constraints are met, so the order can be filled.
Answer:
it would be a 3/15 or 1/5 chance
Step-by-step explanation: