3(6-4x)-27x+10x-31 =
18-12x-27x+10x-31 distributed. =
-13 - 29x
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)
1st photo is simplifying the entire account.
2nd photo is how i simplified the x^2 + 9x + 18 equation into (x+3).(x+6) .
3rd photo is the remaining part of the 2nd photo.
Answer: 2nd option = (x+6)(x+5)
Answer: Angles A and S are congruent
Step-by-step explanation: