-3^3=9
18-9+3•2
9+3•2
12•2
24
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)
(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)
(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)
(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.
2c3 Because when you look at it when you look at the question if I do that and then you were at the AC is at the two and see is that the three on the number line then you would add that on and you’ll get your answer
Answer:
The percentage increase in Jayana's postcard collection is 15%
Step-by-step explanation:
Jayana had 20 postcards last year
With 3 more postcards this year
From the given equation Quantity = Percent x Whole
Here;
Let P = Percent/100%
Quantity = Increment in postcard = 3 postcards
Whole = The total postcards from last year = 20 postcards
Hence,
3 postcards = P x 20 postcards
P = 3/20 = 0.15
Recall P = Percent/100%
∴ Percent = P x 100% = 0.15 x 100% = 15%
The percentage increase in Jayana's postcard collection is 15%
