Can some one help me please god bless you <br><br><br> 25 points

A one-sided hypothesis test for the proportion for a random sample of 50 the z-score of the

Sedaia [141]

Considering that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, it is found that it is significant at the 5% level, but not at the 1% level.

<h3>When a measure is significant?</h3>

If p-value > significance level, the measure is not significant.

If p-value < significance level, the measure is significant.

Using a z-distribution calculator, it is found that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, hence, this is significant at the 5% level, but not at the 1% level.

More can be learned about p-values at brainly.com/question/16313918

6 0

2 years ago

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil

Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

$t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68$

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= $\frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }$

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

4 0

3 years ago

Answer to -13.62-(27.9)

PolarNik [594]

Answer:

− 1049

Step-by-step explanation:

-13.62-(27.9)

Primero los paréntesis:

-13.62-243

Luego continuamos por las multiplicaciones:

-806 - 243

Finalmente obtenemos:

− 1049

Espero te ayude :)

8 0

3 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

4vir4ik [10]

Answer:

(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

$p \pm z*\sigma_{p}$

$\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }$

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

$p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134$

For a 95% two-sided confidence interval, z=±1.96, so

$\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\$

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

$UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787$

The confidence interval is: -∞ ≤ π ≤ 0.0787.

5 0

3 years ago

A trapezoid has 8.2 millimeters base and 5.2 millimeters base, as well as 10 millimeters height. What is the area?

Savatey [412]

Answer:

67 mm

Step-by-step explanation:

use area of a trap formula:

b1+b2 /2*h

b1=base

b2=base

h=height

in our case it was, 8.2+5.2/2*10

67

6 0

2 years ago

Can some one help me please god bless you 25 points