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coldgirl [10]
3 years ago
13

Find the surface area of the composite solid.

Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

<h2>         1240.4 mm²</h2>

Step-by-step explanation:

440.4 + 5\cdot(\frac12\cdot16\cdot20)=440.4+800=1240.4\ mm^2

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Percents! Please answer!!
Fofino [41]

Answer:

39%

Step-by-step explanation:

83-last price

83 last price

100 x ?

100 * last price = 83 . x

x= 39

7 0
3 years ago
Given that G(x) = 5/2 * x - 7/2 what is x if G(x) = 39 Show your work.
mylen [45]

Answer:

5/(760=76

Step-by-step explanation:

6 0
3 years ago
Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.
Lelechka [254]
8x2+8x+9
=16x+8x+9
=24x+9
Are that right
5 0
3 years ago
If a boat depreciates in value according to the simple interest formula Y=20,000(.92)^2 find the rate of decay. Write as a perce
Alexandra [31]

Answer:

Rate of Decay = 8%

Step-by-step explanation:

The decay formula is:

F=P(1-r)^t

Where F is the final value (here, it is given as "Y")

P is the initial value (here, given as 20,000)

r is the rate of decay (what we need to find)

t is the time (given as 2)

Comparing both the equations:

F=P(1-r)^t\\Y=20,000(0.92)^2

We see that:

1 - r  =0.92

We solve for "r":

1 - 0.92 = r

0.08 = r

The rate of decay is 0.08, as a percentage, we need to multiply by 100, so we have:

0.08 * 100 = 8%

Rate of Decay = 8%

6 0
4 years ago
It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig
Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let \mu denotes the average hours of sleep per night.

As per given , we have

H_0:\mu=7\\H_a:\mu

, since H_a is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : \overline{x}=7.24

Sample  standard deviation : s= 1.93

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e.  t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58

For significance level \alpha=0.05 and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= t_{\alpha, df}=t_{0.05,21}=- 1.7207

Decision : Since the test statistic value (0.58) > critical value  1.7207, it means we are failed to reject the null hypothesis .

[Note : When |t_{cal}|>|t_{cri}|, then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0
3 years ago
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