You are driving in Canada and the speed limit is 110 kph (kilometers per hour). How fast is that in mph (miles per hour)?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

The answer is 68 mph. Hope this helps :)

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SOLVE<br> r(s 2) (t) when r = 2, s = 3, and t = 5 <br><br><br> pls help

Keith_Richards [23]

Answer:

320 or 40 sorry if I´m wrong

Step-by-step explanation:

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2 years ago

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Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

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3 years ago

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Without multiplying, tell which is greater: x 45 or x 45 explain.

Vanyuwa [196]

Answer: x45=x45 cannot be greater because they're both equivalent to each other.

Step-by-step explanation:

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3 years ago

Find the value of x using segment addition.

kolbaska11 [484]

You combine both 2x-12 and x+2 and 11 which makes the equation

2x-12+x+2= 11

The you get your answer which is

X=7