3 years ago

X + 2xy- y^2 = 2 find dy/dx using implicit differentiation

1 answer:

8 0

Answer:

hope that helps

Step-by-step explanation:

3x^2+2xy+y2=2

6x + 2y + 2xy' + 2yy' = 0

x=1 ==> y=-1

6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0

6 - 2 + 2y' - 2y' = 0

4 = 0

(e) undefined

The graph is an ellipse. At (1,-1) there is a vertical tangent

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