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Umnica [9.8K]
3 years ago
6

X + 2xy- y^2 = 2 find dy/dx using implicit differentiation

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

hope that helps

Step-by-step explanation:

3x^2+2xy+y2=2

6x + 2y + 2xy' + 2yy' = 0

x=1 ==> y=-1

6(1) + 2(-1) + 2(1)y' + 2(-1)y' = 0

6 - 2 + 2y' - 2y' = 0

4 = 0

(e) undefined

The graph is an ellipse. At (1,-1) there is a vertical tangent

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Vera wants to graph a line that passes through (0,2) and has a slope of 2/3 which points could Vera use to graph a line check al
Naddik [55]
The answer to the question

6 0
3 years ago
Read 2 more answers
Find the percent of change. Original: 80, new: 64
lara31 [8.8K]
Hi there!

To find the percent of change we can use the following formula:
\frac{new - old}{old} \times 100\%

Let's fill in our data
\frac{64 - 80}{80} \times 100\% =

Subtract
\frac{ - 16}{80} \times 100\% =

Divide
- 0.2 \times 100\%

And finally multiply
- 20\%

Hence, the percent of change is negative 20%.
~ Hope this helps you!
3 0
3 years ago
Can you PLEASE help me with this?!
riadik2000 [5.3K]

Step-by-step explanation:

angle B=angle E

5x=45

x=9

4 0
3 years ago
What is the sum of ∞Σn=1 2(1/5)^n-1? s=1/5 s=2/5 s=5/3 s=5/2
lutik1710 [3]

The sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

<h3>How to determine the sum of the notation?</h3>

The sum notation is given as:

∞Σn=1 2(1/5)^n-1

The above notation is a geometric sequence with the following parameters

  • Initial value, a = 2
  • Common ratio, r = 1/5

The sum is then calculated as

S = a/(1 - r)

The equation becomes

S = 2/(1 - 1/5)

Evaluate the difference

S = 2/(4/5)

Express the equation as products

S = 2 * 5/4

Solve the expression

S= 5/2

Hence, the sum of the sum notation ∞Σn=1 2(1/5)^n-1 is S= 5/2

Read more about sum notation at

brainly.com/question/542712

#SPJ1

7 0
2 years ago
Can someone please help me????
azamat
Does the rate of change equal for each.
take the output difference and divide by the input distance
1st -5/10 = -1/2
2nd -1/2
3rd -5/10.= -1/2
3 0
3 years ago
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