I think the answer is C but I could be wrong
Answer:
The receiver will not detect the error.
Explanation:
The byte sent by transmitter: 10101010
The byte received by receiver due to channel noise: 10011010
If you see the bold part of the both sent and received bytes you can see that the number of bits changed is 2.
The two communicating devices are using a single-bit even parity check. Here there are two changed bits so this error will not be detected as this single bit even parity check scheme has a limit and it detects the error when the value of changed bit is odd but here it is even.
This parity scheme basically works well with the odd number of bit errors.
Answer:
the answer would be B proxy server
Answer:
Caesar cipher
Explanation:
In formation technology, cryptography or cryptology is a process of coding or encrypting information, using algorithms and input values in a network, where there is a present of a third party called adversaries or attackers.
There are different types of cryptography, namely, symmetric, assymmetric and hash cryptography.
Ciphers are algorithms used in cryptography to encode (encrypt) or decode (decrypt) information. An example of cipher is the Ceasar's cipher.
Ceasar cipher is a simple type of substitution cipher that encrpts plain text one character at a time and each coded character depends on the single character and a fixed distance value.