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steposvetlana [31]
3 years ago
11

How many seconds are required to make a left turn and join traffic?​

Computers and Technology
2 answers:
Westkost [7]3 years ago
8 0
In town: 5-8 seconds
On highways: 10-20 seconds
algol [13]3 years ago
7 0
City - 5-10 seconds
Highway 10-20 seconds
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Find the inverse function of f(x)= 1+squareroot of 1+2x
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Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

x=1+\sqrt{1+2y}

\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+\sqrt{1+2y}-1=x-1

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\sqrt{1+2y}=x-1

\mathrm{Square\:both\:sides}

\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2

\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y

\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1

1+2y=x^2-2x+1

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+2y-1=x^2-2x+1-1

\mathrm{Simplify}

2y=x^2-2x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}

\mathrm{Simplify}

y=\frac{x^2-2x}{2}

Therefore the inverse function of f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

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