Answer:
Following are the program in the C++ Programming Language.
#include <iostream> //header file
#include <cmath> //header file
using namespace std; //namespace
//define function
void quadratic (double a, double b, double c)
{
double x,y; //set double type variables
//check a==0
if (a==0)
{ //then print message
cout << "no solution for a=0";
}
//check if solution is less than 0
else if ((b*b - 4*a*c) < 0)
{ //print message
cout << "no real solutions";
}
//otherwise
else
{//solve the following quadratic equation
x = (-b + sqrt( b*b - 4*a*c)) /(2*a);//in term of x
y = (-b - sqrt(b*b - 4*a*c)) / (2*a);//in term of y
//check x is greater than y
if (x > y){
cout<<x; //print the value of x
}
//otherwise
else{
cout<<y;//print the value of y
}
}
}
//define main method
int main() {
//set double type variables and assign their value
double x=10, y=50, z=-205;
//call the function
quadratic(x,y,z);
}
<u>Output</u>:
2.67204
Explanation:
Here, we define a function "quadratic" and pass three double data type variables i.e., "a", "b" and, "c" inside the function.
- Set two double type variable i.e., "x", "y".
- Set the if conditional statement and check the conditions is the variable a is equal to the 0 then, print the message or check another condition is the solution of the equation "b*b - 4*a*c" is less than 0, then print the message.
- Otherwise, solve the quadratic equation in terms of the variable x or the variable y.
- Again check the condition inside the else part is the variable x is greater than the variable y then, print the value of x otherwise print the value of y.
Finally, we define the main function inside it we set three double type variables i.e., "x", "y" and, "z" and initialize value 10, 50 and, -250 then, call the function and pass the variables x y z in its parameter.
