Answer:

Step-by-step explanation:
The radius is the distance between the center and any point on the circle.
The formula of a distance between two points:

We have the center (3, -3) and other point on the circle (7, 6).
Substitute:

9514 1404 393
Answer:
(3, 1)
Step-by-step explanation:
We assume you want the solution to the system ...
The second equation gives a nice expression for x, so we can use that in the first equation.
2(y+2) -3y = 3 . . . . substitute for x in the first equation
2y +4 -3y = 3 . . . . . eliminate parentheses
-y = -1 . . . . . . . . . . . collect terms, subtract 4
y = 1 . . . . . . . . . . . . multiply by -1
x = 1 +2 = 3 . . . . . . substitute for y in the second equation
The solution is (x, y) = (3, 1).
The pattern of a linear function, is the following:
y = mx + b
Where m is always the slope.
m in this case is -4, hence
The correct answer for your question is -4.
Answer:
The answer is A.
Step-by-step explanation:
I learned it before.
Hope this helps.
Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:

(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)