Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
<span> remainder is f(3) </span>
<span>3^3 - 6*3^2 - 9*3 + 3 </span>
<span>= 27 - 54 - 27 + 3 </span>
<span>= -51</span>
The sine of any acute angle is equal to the cosine of its complement. the cosine of any angle is equal to the sine of its complement also
Answer: 5.044 0z is not pineapple juice
Step-by-step explanation:
total amount of mixed fruit juice: 6.45 oz (oz stands for ounce)
pineapple juice: 1.406 oz
total - pineapple juice=not pineapple juice
6.45 - 1.406=5.044 oz
Hope this helps!! :)
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