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2 years ago

PLEASE ANSWER FAST

Mathematics

2 answers:

masha68 [24]2 years ago

6 0

Answer:

I think the answer is A. Hope this helps!

Step-by-step explanation:

BaLLatris [955]2 years ago

3 0

I think the awnser is A

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DochEvi [55]

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Step-by-step explanation:

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2 years ago

the temper ire of chicken soup is 192.7 F as it cools the temperature of the soup decreases 2.3 what is the temperature of the s

ad-work [718]

The temperature of soup after 25 minutes is $135.2^{\circ}\ F$

Solution:

The temperature of chicken soup is 192.7°F

As it cools, the temperature of the soup decreases 2.3°F per minute

Let the initial temperature be $T_0$

Let "t" be the time for rate of decrease

Set up an equation

Temperature = Initial temperature - decrease in temperature

Decrease in temperature = rate of decrease x time

Therefore,

$T = T_0-2.3t$

To find the temperature of soup after 25 minutes, substitute t = 25

$T = 192.7 - 2.3 (25)\\\\T = 192.7 -57.5\\\\T = 135.2$

Thus the temperature of soup after 25 minutes is $135.2^{\circ}\ F$

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2 years ago

Solve the following system of equations by elimination

olya-2409 [2.1K]

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

-x -2y = 11

-1 -(2*-6) = 11

-1 -(-12) = 11

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2 years ago

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