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Leya [2.2K]
4 years ago
6

A random sample of 150 people was taken from a very large population. ninety of the people in the sample were female. the standa

rd error of the proportion is
Mathematics
2 answers:
Andre45 [30]4 years ago
8 0

Answer:  0.04

Step-by-step explanation:

  • The standard error of the proportion is basically gives the spread of the sample proportions about the population mean.

Given : Sample size : n= 150

No. of females in the sample  : x= 90

Proportion of females = \hat{p}=\dfrac{x}{n}=\dfrac{90}{150}=0.6

Standard error of proportions :

SE=\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}} , where \hat{p} = sample proportion and n= sample size .

Substitute the corresponding values , we get

SE=\sqrt{\dfrac{0.6(1-0.6)}{150}}

SE=\sqrt{\dfrac{0.6 (0.4)}{150}}

SE=\sqrt{0.0016}=0.04

Hence, the standard error of the proportion is 0.04 .

Rus_ich [418]4 years ago
4 0
The standard error is 100% as females cannot be 90% of the population.
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AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

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4 years ago
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gulaghasi [49]
You can make 96 cookies
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If you are good at determining sequences please help! (Show work)
ziro4ka [17]

Answer:

-62.5008

Step-by-step explanation:

the pattern here is dividing by -5, so just continue dividing by -5 starting on -3 and continuing 4 more times. record each number and then add them together using a calculator. you will get -62.5008

Please mark brainliest :)

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3 years ago
An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insu
ankoles [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

An insurance company examines its pool of auto insurance customers and gathers the following information: (i) All customers insure at least one car. (ii) 70% of the customers insure more than one car. (iii) 20% of the customers insure a sports car. (iv) Of those customers who insure more than one car, 15% insure a sports car. Calculate the probability that a randomly selected customer insures exactly one car, and that car is not a sports car?

Answer:

P( X' ∩ Y' ) = 0.205

Step-by-step explanation:

Let X is the event that the customer insures more than one car.

Let X' is the event that the customer insures exactly one car.

Let Y is the event that customer insures a sport car.

Let Y' is the event that customer insures not a sport car.

From the given information we have

70% of customers insure more than one car.

P(X) = 0.70

20% of customers insure a sports car.

P(Y) = 0.20

Of those customers who insure more than one car, 15% insure a sports car.

P(Y | X) = 0.15

We want to find out the probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

P( X' ∩ Y' ) = ?

Which can be found by

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

From the rules of probability we know that,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )    (Additive Law)

First, we have to find out P( X ∩ Y )

From the rules of probability we know that,

P( X ∩ Y ) = P(Y | X) × P(X)       (Multiplicative law)

P( X ∩ Y ) = 0.15 × 0.70

P( X ∩ Y ) = 0.105

So,

P( X ∪ Y ) = P(X) + P(Y) - P( X ∩ Y )

P( X ∪ Y ) = 0.70 + 0.20 - 0.105

P( X ∪ Y ) = 0.795

Finally,

P( X' ∩ Y' ) = 1 - P( X ∪ Y )

P( X' ∩ Y' ) = 1 - 0.795

P( X' ∩ Y' ) = 0.205

Therefore, there is 0.205 probability that a randomly selected customer insures exactly one car, and that car is not a sports car.

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3 years ago
Help I don’t know the answer I have tried solving this all kinds of different ways and it’s still wrong!
gogolik [260]

Answer:

24

Step-by-step explanation:

I think it's 24 I don't knowI say I think

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3 years ago
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