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Mazyrski [523]
3 years ago
7

RX: Keflex 125 mg, take 10 ml by mouth 4 times a day for 10 days How many mg will the patient have taken at the end of 10 days?

If there are only 120 ml vials available, how many vials will be used to fill this prescription
Mathematics
1 answer:
Lorico [155]3 years ago
3 0

Answer:

400ml will be taken at the end of 10days

280ml will be used to fill this prescription

Step-by-step explanation:

10ml four times a day = 40ml per day

Therefore 10days = 40 x 10 = 400ml

If there is only 120ml available.

400ml - 120ml = 280ml

280ml will be used to fill this prescription

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What adds to -9, and multiplies to -70?
dybincka [34]
-14 and 5 (-14+5 = -9) and -14*5) = -70

Make me the brainliest answer.
4 0
4 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
3 years ago
PLEASE HELP ASAP IM STUCK HELP PLEASE
sasho [114]

Answer:

x>-2  and x<5

-2 <x<5

Step-by-step explanation:

We have open circles at -2 and 5 and are between the two numbers so we have and AND statement. It can be written either

x>-2  and x<5

or

-2 <x<5

6 0
3 years ago
The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 1600 vo
Arturiano [62]

Answer:

Test statistic = -2.44

There is enough evidence to support the strategist's claim.

Step-by-step explanation:

H0 : p = 0.41

H1 : p < 0.41

pˆ = 0.38

Test statistic :

z=pˆ−p/√p(1−p)/n

Z = (0.38 - 0.41) / √(0.41(1 - 0.41) / 1600

Z = - 0.03 / √0.0001511875

Z = - 0.03 / 0.0122958

Z = - 2.4399

Test statistic = -2.44

The Pvalue :

P(Z < -2.44) = 0.0073436

α - level = 0.02

If Pvalue < α ; Reject H0

0.0073436 < 0.02 ; We reject H0

Since Pvalue < α ; Hence, There is enough evidence to support the strategist's claim.

8 0
3 years ago
I REALLY NEED HELP!
anastassius [24]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3700\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &7 \end{cases} \\\\\\ A=3700e^{0.045\cdot 7}\implies A=3700e^{0.315}\implies A\approx 5069.96

8 0
3 years ago
Read 2 more answers
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