Answer:
Option B is correct.
Step-by-step explanation:
4x+3y-z= -6 eq(1)
6x-y+3z= 12 eq(2)
8x+2y+4z=6 eq(3)
We need to solve these equations and find the value of x, y and z.
Multiply equation 2 with 3 and then add equation 1 and 2
18x -3y +9z = 36
4x +3y -z = -6
_____________
22x + 8z = 30 eq(3)
Multiply equation 2 with 2 and add with equation 3
12x -2y + 6z = 24
8x +2y +4z = 6
____________
20x + 10 z = 30 eq(4)
Multiply equation 3 with 10 and equation 4 with 8 and then subtract
220x + 80z = 300
160x + 80z = 240
- - -
_________________
60x = 60
x= 60/60
x= 1
Putting value of x in equation 3
22x + 8z = 30
22(1) + 8z = 30
8z = 30 - 22
8z = 8
z = 8/8
z=1
Putting value of x and z in equation 1
4(1)+3y-(1)=-6
4 + 3y -1 = -6
3 + 3y = -6
3y = -6 -3
3y = -9
y = -3
so, Option B x=1, y=3 and z=1 is correct
Start off by writing the equation y = mx - b. Then plug in what you do know
3 = 2(-1) - b (m is the slope and parallel lines have the same slope). Then solve
3 = -2 - b
<u>+2 +2</u>
5 = b
So y = 2x + 5
The altitudes of equal length, BE and CF gives AB = AC, from which we have;
- ∆ABC is an isosceles triangle
<h3>How can the RHS rule be used to indicate an isosceles triangle?</h3>
From the given description, we have;
BE = CF
<CFB = <BEC = 90° All right angles are congruent
BC = BC by reflexive property of congruency
BC = The hypotenuse side of triangles ∆BFC and ∆CEB
Therefore;
∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.
Therefore;
BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Similarly, we have;
∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency
Which gives;
FA = AE by CPCTC
BF + FA = CE + AE, by substitution property of equality
BF + FA = AB
CE + AE = AC
Therefore;
Therefore;
- ∆ABC is an isosceles triangle
Learn more about rules of congruency here:
brainly.com/question/24261247
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The GCF is of 11ab +32ab is 43ab
F(x)=5x-2
y=5x-2
y=5(3)-2
y=15-2
y=13
so the answer is B. 13
