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Digiron [165]
3 years ago
6

Use the unit circle to find the inverse function value in degrees.

Mathematics
1 answer:
leva [86]3 years ago
5 0
D 30 degrees that's the answer.
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In the figure below, m∠1 = 46°. Find m∠2​
pickupchik [31]

Answer:

if its a 90 degree angle u will  say 90 -46 to get m<2

if is a 180 degree angle u will say 180-46 to get m<2

hope this helped :) brainliestn pls

5 0
3 years ago
What is the perimeter of a rhombus whose diagonals measure 42cm and 56cm?
Trava [24]

Answer:

676

Step-by-step explanation:

d1×d2/2

42×56/2

1352/2=676

please check it by doing again

3 0
3 years ago
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What is the length of the hypotenuse of the right triangle? Enter your answer in the box.
ki77a [65]

Answer:

10 ft

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

let h be hypotenuse, then

h² = 6² + 8² = 36 + 64 = 100 ( take the square root of both sides )

h = \sqrt{100} = 10

The hypotenuse is 10 ft

5 0
3 years ago
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The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
Plz help quick. This question is on a quiz in Edg 2020 whoever answered first will get brainliest and I will be giving 50 points
lys-0071 [83]

Answer:

A B and D

Step-by-step explanation:

4 0
3 years ago
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