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CaHeK987 [17]
3 years ago
8

If 2/5n+4=20, what is the value of n?

Mathematics
1 answer:
Dimas [21]3 years ago
6 0
2/5n + 4 = 20
/5 /5
2n + 4 = 100
- 4 -4
2n = 96
/2 /2
n = 48

The answer to your question is 48
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A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a coll
xxMikexx [17]

Answer: D

H0: μ=522

H1: μ>522

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

So, for this case;

The null hypothesis is that the mean score equals to 522

H0: μ=522

The alternative hypothesis is that the mean score is greater than 522.

H1: μ>522

8 0
3 years ago
On december 1, jonas jewelry wholesale center started with an inventory of 1,000 watches. shipments of 168, 231, and 411 were se
denis-greek [22]

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Total watches in an inventory = 1000

Number of shipments sent out = 168, 231, 411

So, Remaining inventory of watches would be :

1000-(168+231+411)\\\\=1000-810\\\\=190

New receipts = 21, 145 and 11

So, Number of watches on hand becomes :

190+(21+145+11)\\\\=367

Hence, Third option is correct.

5 0
3 years ago
What is the y-coordinate for the solution to the following system of equations?
AURORKA [14]
6x + 9y =36 is the Answer
6 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
During the walk-a-thon, brian walks 3 and one fourth kilometers, and Stacy walks 2 and seven eighths kilometers. How many more k
BARSIC [14]

Answer:

3/8 or three eighths

8 0
3 years ago
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