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sergij07 [2.7K]
3 years ago
10

The sum of two numbers is 54 and the difference is 8. What are the numbers?

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

23 and 31 are the numbers you are searching for.

Step-by-step explanation:

23 + 31 = 54

31 - 23 = 8

Have a nice day!

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Im almost done with it
baherus [9]

Answer:

Area of rectangle = \mathbf{x^2-4x}

Perimeter of rectangle = \mathbf{4x-8}

Step-by-step explanation:

We are given:

Length of rectangle = x

Width of rectangle = x-4

We are not given if we want to find area of rectangle or perimeter of rectangle.

So, I will be finding both

Area of rectangle

The formula used is: Area\: of\: rectangle=Length \times Width

Putting values and finding area

Area\: of\: rectangle=Length \times Width\\Area\: of\: rectangle=x \times (x-4)\\Area\: of\: rectangle=x^2-4x

So, we get area of rectangle = \mathbf{x^2-4x}

Perimeter of rectangle

The formula used is: Perimeter \: of\: rectangle=2(Length+ Width)

Putting values and finding perimeter

Perimeter \: of\: rectangle=2(Length+ Width)\\Perimeter \: of\: rectangle=2(x+ x-4)\\Perimeter \: of\: rectangle=2(2x-4)\\Perimeter \: of\: rectangle=4x-8

So, we get perimeter of rectangle = \mathbf{4x-8}

I hope, it can help in solving the question.

4 0
3 years ago
Technology is also known as Applied Science because it involves "using" science to make something useful for mankind.
goblinko [34]

Answer:

true

Step-by-step explanation:

The terms 'technology' and 'applied science' will be taken here as synonymous, although neither is adequate: in fact, 'technology' sug- gests the study of practical arts rather than a scientific discipline, and 'applied science' suggests the application of scientific ideas rather than that of the scientific method

5 0
3 years ago
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What is the difference between integers and real numbers?
galina1969 [7]
Integers are positive and negative whole numbers no fractions or decimals.
Real numbers do have fractions and decimals that integers do not.
5 0
3 years ago
Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere
Ket [755]

Answer:

e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...

\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...

This expansion is valid only if \text{f}\:^{(n)}(a) exists and is finite for all n \in \mathbb{N}, and for values of x for which the infinite series converges.

\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1

\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...

\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If  $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}

\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4

\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4

\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4

Substituting the values in the series expansion gives:

e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...

Factoring out e⁴:

e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right]

<u>Taylor Series summation notation</u>:

\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n

Therefore:

\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n

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Compound Probability
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Answer:

9/7is the chance of coming red ball

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