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3 years ago

What is the area of Triangle PQR on the grid?

Mathematics

2 answers:

kupik [55]3 years ago

6 0

Answer:

4 units

Step-by-step explanation:

You have a triangle. This means that the formula is 1/2 x b x h. So its 2 x 4 = 8. Then its 8 x 1/2 which gives you 4.

Darina [25.2K]3 years ago

5 0

Answer:

its just 4

Step-by-step explanation:

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The area of a rectangle is 1,036 cm and its length is 74 cm.

Nikitich [7]

Answer:

(i) Breadth = 14 cm

(ii) Perimeter = 176 cm

Step-by-step explanation:

Given,

Area of a rectangle = $1036$ cm²

Length = $74$ cm

(i) Breadth = ?

We know that, Area of a rectangle = length × breadth.

Then,

$1036 = 74 \times Breadth\\1036 \div 74 = Breadth\\\boxed{\bf\:14 \:cm = Breadth }$

(ii) Perimeter of a rectangle = 2 (length + breadth)

Then,

$Perimeter = 2(74 + 14)\\Perimeter = 2(88)\\\boxed{\bf\: Perimeter = 176 \: cm}$

$\rule{150pt}{2pt}$

8 0

2 years ago

Write the absolute value inequality in the form x−b ≤c or x−b ≥c that has the solution set −1≤x≤3.

stealth61 [152]

Answer:

|x - 1| ≤ 2

Step-by-step explanation:

b = (-1+3)/2 = 1

c = 3-1 = 2

|x - 1| ≤ 2

4 0

3 years ago

Pls someone help me I don't understand!! if correct I'll make Brainliest!!!!

Georgia [21]

Every hour there is 15 gallons of water added to the tank. In 10 hours there will be 150 gallons of water in the tank.

Hope this helps :)

5 0

3 years ago

Juliette made the jewelry box shown below.The jewelry bow was shaped like a right rectangular prism

VMariaS [17]

44 I think cause 8times5=40plus 4 equals 44

6 0

3 years ago

Read 2 more answers

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

4 years ago

Read 2 more answers