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inna [77]
3 years ago
13

Find two consecutive off integers such that their product os 35 more than 8 times their sum

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0
Let the numbers be x and x + 1
x(x + 1) = 35 + 8(x + x + 1)
x^2 + x = 35 + 8(2x + 1)
x^2 + x = 35 + 16x + 8
x^2 + x - 16x = 43
x^2 - 15x - 43 = 0
x = 17.46 or -2.46 which are not integers.
So, check your question and make sure you wrote it well
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Please help me!! ✍ <br> Thank you!! ♛<br> Answers are included! ♒
tino4ka555 [31]
THat would be A , B, C and E
4 0
3 years ago
3[–x + (2 x + 1)] = x – 1
photoshop1234 [79]

Answer:

<h3>x = -2</h3>

Step-by-step explanation:

3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\

Collect like terms

3x -x =-1-3

Add similar elements

2x = -4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{-4}{2}\\\\Simplify\\\\x = -2

3 0
3 years ago
4h = 17 <br> what is the letter H?
Dafna1 [17]

Answer:

4.25

Step-by-step explanation:

6 0
3 years ago
Write a formula for this sequence: 8,-1,-10,-19
Romashka [77]
This is an arith. sequence, and the common difference is -9.

a(n+1) = a(n)-9, with a(1)=8.  Thus, if we look at the first term, we see 8; subracting 9 from 8 produces the second term (-1).
4 0
3 years ago
Find the average rate of change of the function over the given interval.
Minchanka [31]

Answer:

Average rate of change = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

Step-by-step explanation:

The average rate of change of the function

F(t) = 2t^2 - 1 ,  [ 5,5.1 ]

solution

\frac{f(5.1)-f(5)}{5.1 - 5} = \frac{2*(5.1)^2-1-(2*5^2-1)}{0.1}   = [ 2 ( 26.01 - 25 ) / 0.1 ]

= 2.02 / 0.1 = 20.2

Rate of change at the left endpoint :   f' (5) = 4t = 20

Rate of change at the right  endpoint : f' (5.1) = 4*5.1 = 20.4

6 0
4 years ago
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