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faltersainse [42]
3 years ago
12

Sample Run 1 Enter your word: zebras Enter a number: 62 Password not long enough. Sample Run 2 Enter your word: newyorkcity Ente

r a number: 892 Password: [email protected] y892
Computers and Technology
1 answer:
Aliun [14]3 years ago
5 0

Answer:

import random

paswrd = input("Enter Pass: ")

while len(paswrd) < 8:

print('Password not long enough.')

paswrd = input("Enter Pass: ")

paswrd = paswrd.replace('e', '@')

paswrd = paswrd.replace('E', '@')

paswrd = paswrd.replace('s', '$')

paswrd = paswrd.replace('S', '$')

paswrd = paswrd.replace('t', '+')

paswrd = paswrd.replace('T', '+')

paswrd = paswrd.capitalize()

paswrd = paswrd + (str(random.randint(1,999)))

print(paswrd)

Explanation:

  • Take the password as input from user.
  • Replace the alphabets with relevant characters.
  • Capitalize the password.
  • Finally display the password.
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Answer:

That

your answer

MAC address filtering

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1. what do to call the process of preserving food by soaking the raw ingredient in salt and water solution.
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Answer:

Salting is the preservation of food with dry edible salt. It is related to pickling in general and more specifically to brining also known as fermenting (preparing food with brine, that is, salty water) and is one form of curing.

Explanation:

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What is analog computer? where is it used​
hichkok12 [17]

Explanation:

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3 years ago
Read 2 more answers
4.3 mini programs AP computer science
allochka39001 [22]

1.

name = input("Enter your name: ")

num1 = int(input("Hello "+name+ ", enter an integer: "))

num2 = int(input(name+", enter another integer: "))

try:

   if num1 % num2 == 0:

       print("The first number is divisible by the second number")

   else:

       print("The first number is not divisible by the second number")

except ZeroDivisionError:

   print("The first number is not divisible by the second number")

try:

   if num2 % num1 == 0:

       print("The second number is divisible by the first number")

   else:

       print("The second number is not divisible by the first number")

except ZeroDivisionError:

   print("The second number is not divisible by the first number")

2.

import random, math

num1 = float(input("Enter a small decimal number: "))

num2 = float(input("Enter a large decimal number: "))

r = round(random.uniform(num1, num2), 2)

print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))

I hope this helps!

8 0
3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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