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4 years ago

78 is 15% of what number? Solve using an equation. Show your work.

Mathematics

1 answer:

Phoenix [80]4 years ago

4 0

Answer:

520

Step-by-step explanation:

78 = 15% × (what number)

78/0.15 = (what number) = 520

78 is 15% of 520.

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1. What is the solution to 5 + t = 23 a. T=28 b. T=18 c. T= -18 d. T= -23 2. What is the value of b if -7 + b = -8 a. B=15 c. B=

kramer

The answer to number one is 18 and the answer to number two is -1

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3 years ago

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How many liters would 60 mega-liters be?<br> Help

san4es73 [151]

Answer:

6e+7

Step-by-step explanation:

divide the volume value by 1e+6

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4 years ago

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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 mi/h slower than the other. If

maw [93]

Answer:

1478 mi/h

Step-by-step explanation:

The rate of change is the distance divided by the time.

$\text{Rate of change} = \dfrac{\text{distance}}{\text{time}} = \dfrac{\text{2956 mi}}{\text{2 h}} = \textbf{1478 mi/h}$

4 0

3 years ago

V(t)=875-50t

Mandarinka [93]

Use socratic instead of this

6 0

3 years ago

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

8 0

3 years ago