see the attached figure to better understand the problem
we know that
in the right triangle ABC
cos 56°=AC/AB
where
AC is the adjacent side to angle 56 degrees------> the distance from the surveyor to the building
AB is the hypotenuse-----> 148 ft 2 in
56 degrees------> is the angle of elevation
so
cos 56°=AC/AB---------> solve for AC
AC=AB*cos 56°
AB=148 ft 2 in
convert 2 in to ft
1 ft -----> 12 in
x ft------> 2 in
x=2/12-----> x=0.17 ft
AB=148 ft 2 in-----> 148 ft+0.17 ft------> AB=148.17 ft
AC=AB*cos 56°----> AC=148.17*cos 56°------> AC=82.86 ft
convert 0.86 ft to in
0.86 ft=0.86*12-----> 10.32 in
distance AB=82 ft 10 in
the answer is
the distance from the surveyor to the building is 82 ft 10 in
Answer:
13 units
Step-by-step explanation:
D is at (1,6) and C is at (-4,-6)
The distance is found by
d = sqrt(( y2-y1)^2+ (x2-x1)^2))
= sqrt( ( -6-6)^2 + (-4-1)^2)
= sqrt( -12^2 + -5^2)
= sqrt( 144+ 25)
= sqrt( 169)
= 13
Answer: The costs are 8.4% of the total revenue.
The stadium is going to make $750,000 for the naming rights of the stadium. The cost to the stadium is on $63,000.
To find the percent, we have to divide the two values and multiply by 100.
63000 / 750000 x 100 = 8.4%
Answer:
-4
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
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