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3 years ago

Which expression completes the statement to form a true equation? 28–3+2= A. 3³ B. 5(4 + 2) C. 3² + 19 D. 44–24

1 answer:

6 0

Hi!

So first, let's find what the original equation equals.

28 - 3 + 2 = ?
25 + 2 = ?
27

Now let's go through each answer choice, and find one that equals 27.

3^3 = 27
5(4 + 2) = 30
3^2 + 19 = 28
44-24 = 20

The answer is A. 3³

Hope this helps! :)

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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3 years ago

What is the number name for 3,152,308

Gemiola [76]

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2 years ago

Read 2 more answers

The ratio of the side lengths of a quadrilateral is 3:2:6:7, and its perimeter is 126 meters. What is the length of the shortest

scoundrel [369]

since the lengths of all those four sides are in a 3:2:6:7 ratio, and the whole perimeter is 126, what we do is, simply divide the whole by (3+2+6+7) and distribute accordingly.

$\bf \stackrel{3\cdot \frac{126}{3+2+6+7}}{3}~~:~~\stackrel{2\cdot \frac{126}{3+2+6+7}}{2}~~:~~\stackrel{6\cdot \frac{126}{3+2+6+7}}{6}~~:~~\stackrel{7\cdot \frac{126}{3+2+6+7}}{7} \\\\\\ 3\cdot \cfrac{126}{18}~~:~~2\cdot \cfrac{126}{18}~~:~~6\cdot \cfrac{126}{18}~~:~~7\cdot \cfrac{126}{18} \\\\\\ 21~~:~~\stackrel{shortest}{14}~~:~~42~~:~~49$