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4 years ago

Wyatt solved the following equation:

Mathematics

1 answer:

NikAS [45]4 years ago

6 0

Answer:

Option B

Step-by-step explanation:

The question is as following:

$x+\frac{1}{2} (6x-4) =6$

Step Work Justification

1 2x + 6x − 4 = 12

2 8x − 4 = 12

3 8x = 16

4 x = 2

Which of the following has all of the correct justifications Wyatt used to solve this equation?

A. Distributive property. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

B. Multiplication property of equality. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

C. Distributive property. 2. Combine like terms. 3. Subtraction property of equality. 4. Division property of equality.

D. Multiplication property of equality. 2. Combine like terms. 3. Subtraction property of equality. 4. Division property of equality

The answer:

Step Work Justification

multiply both sides by 2

1) 2x + 6x − 4 = 12 ⇒ {Multiplication property of equality}

{Combine like terms}

2) 8x − 4 = 12 ⇒

Adding 4 both sides

3) 8x = 16 ⇒ {Addition property of equality}

divide both sides by 8

4) x = 2 ⇒ {Division property of equality}

The answer is option B

(B) Multiplication property of equality. 2. Combine like terms. 3. Addition property of equality. 4. Division property of equality.

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Please help I will award

Fynjy0 [20]

Answer:

17.) A = 17.5 cm squared

18.) A = 36

Step-by-step explanation:

17.) 7 x 5 x 1/2

7 x 5 = 35

35 x 1/2 = 17.5

18.) 8 x 9 x 1/2

8 x 9 = 72

72 x 1/2 = 36

I hope this helped. I am sorry if you get this wrong.

6 0

3 years ago

All Seasons Plumbing has two service trucks that frequently need repair. If the probability the first truck is available is .75,

astra-53 [7]

Answer:

5% probability neither truck is available

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that the first truck is available.

B is the probability that the second truck is available.

We have that:

$A = a + (A \cap B)$

In which a is the probability that the first truck is available and the second one is not $A \cap B$ is the probability that both trucks are available.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that both trucks are available is .30.

This means that $A \cap B = 0.3$

The probability the second truck is available is .50

This means that $B = 0.5$ . So

$B = b + (A \cap B)$

$0.5 = b + 0.3$

$b = 0.2$

The probability the first truck is available is .75

This means that $A = 0.75$ . So

$A = a + (A \cap B)$

$0.75 = a + 0.3$

$a = 0.45$

The probability that at least one truck is available is:

$A \cup B = a + b + (A \cap B) = 0.45 + 0.2 + 0.3 = 0.95$

The probability that neither truck is available is:

$1 - (A \cup B) = 1 - 0.95 = 0.05$

5% probability neither truck is available

6 0

3 years ago

during his first year as a pilot, rob flies 6,692 miles. he flies 16,429 miles the second year and 24,211 miles the third year.

emmainna [20.7K]

First years flies = 6,692 miles ≈7000 miles.

Second year flies = 16,429 miles ≈ 16000.

Third year flies = 24,211 miles ≈ 24000

Total number of miles flies in first and second year = 7,000miles +16,000 miles

Number of more miles he flew in the third year than the first and second year combined = Number of miles flies in third year - Total number of miles flies in first and second year

Number of more miles he flew in the third year than the first and second year combined 24,000 - (7,000+16,000)

Therefore, 24,000 - (7,000+16,000) estimation of how many more miles he flew in the third year than the first and second year combined.

6 0

3 years ago

Can someone please help me on this question?

yan [13]

Answer: q³⁰

Explanation:

First just solve the first part using the exponent rules

p²q⁵ becomes 1/p-⁸q-²⁰ then we flip the fraction so the exponents become positive. Now we have p⁸q²⁰.

Before multiplying the other equation, we must simplify. p-⁴q⁵ becomes 1/p⁴q-⁵ and since it's the exponents being raised to a power we simply multiply the inner exponents times the outer exponent which yields 1/p⁸q-¹⁰. We must make q-¹⁰ positive so we will then bring it to the numerator of the fraction which gives us: q¹⁰/p⁸.

Multiply q¹⁰/p⁸ * p⁸q²⁰/1 = p⁸q³⁰/p⁸ divide the p exponents by each other which yields 0 since when u divide exponents you just subtract them so 8 - 8 = 0. Your answer is now q³⁰/1 or just q³⁰

4 0

4 years ago

Please i need help with this please

Over [174]

Answer:

Your answer would be 9.

Step-by-step explanation:

You always do parenthesis first, 9-6 is 3, then you would do division 3÷3 is 1 then you multiply 4×2 and that would be 8, finally you would at the 8 and the 1 and that would give you 9 as your answer. Hope this helps

7 0

3 years ago