Answer:
Students level of knowledge is higher in accountancy (Y) compared to statistics (X).
Step-by-step explanation:
The level of knowledge of the students in each subject can be known by comparing the mean score of the subjects.
Marks of the students in statistics (X) are: 63 64 62 32 30 60 47 46 35 28
mean = 
= 
= 46.7
The mean mark of students in statistics (X) is 46.7.
Marks of students in accountancy (Y) are: 68 66 35 42 26 85 44 80 33 72
mean = 
= 
= 55.1
The mean mark of students in accountancy (Y) is 55.1.
It can be inferred that students level of knowledge is higher in accountancy (Y) compared to statistics (X).
The answer to this question would be
y
=
1
6
x
+
3
Answer:
I do not know, if you ca rewrite that would be helpful
Step-by-step explanation:
-4x+4x +5y +6y = 17-6
11y=11
divide both side by 11 to isolate y
y=1
4x+6(1) = -6
subtract 6 on both sides
4x=-12
divide 4 on both sides
x=-3
Answer:
a) See the proof below.
b) 
Step-by-step explanation:
Part a
For this case we assume that we have the following series
and this series has a finite radius of convergence
and we assume that
for all n, this information is given by the problem.
We assume that the series converges at the point
since w eknwo that converges, and since converges we can conclude that:
For this case we need to show that converges also for 
So we need to proof that 
We can do some algebra and we can rewrite the following expression like this:
and we see that the last series is alternating.
Since we know that
converges then the sequence {
} must be positive and we need to have
And then by the alternating series test we can conclude that
also converges. And then we conclude that the power series
converges for
,and that complete the proof.
Part b
For this case we need to provide a series whose interval of convergence is exactly (-1,1]
And the best function for this 
Because the series
converges to
when
using the root test.
But by the properties of the natural log the series diverges at
because
and for
we know that converges since
is an alternating series that converges because the expression tends to 0.