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UkoKoshka [18]
3 years ago
14

Bare with me, fractions.

Mathematics
2 answers:
Anettt [7]3 years ago
6 0

\fbox{Option C} is correct as \dfrac{1}{3}\left( {3x} \right) is equal to x an it is equal to inverse x.

Further explanation:

A function that is a reverse of another function is known as an inverse function. If we substitute x in a function f and it gives a result of y then its inverse z to y gives the result x.

Given:

The function f\left( x \right) = 3x and g\left( x \right) = \dfrac{1}{3}x

We have to verify that g\left( x \right) is the inverse of f\left( x \right).

To verify that g\left( x \right) is the inverse of f\left( x \right) we have to show that \left( {f \circ g} \right)\left( x \right) = \left( {g \circ f} \right)\left( x \right).

First we have to find \left( {f \circ g} \right)\left( x \right).

\left( {f \circ g}\right)\left( x \right) can be obtained as,  

\left( {f\circ g} \right)\left( x \right) = f\left( {g\left( x \right)} \right).

Substitute \dfrac{1}{3}x for g\left( x \right) in above equation to obtain \left( {f \circ g} \right)\left( x \right).

\begin{gathered}\left( {f \circ g}\right)\left( x \right) = f\left( {\frac{1}{3}x} \right) \\= 3\left( {\frac{1}{3}x}\right)\\=x\end{gathered}

Now, we have to find \left( {g \circ f} \right)\left( x \right).

\left( {g \circ f} \right)\left( x \right) can be obtained as,  

\left( {g \circ f} \right)\left( x \right) = g\left( {f\left( x \right)} \right).

Substitute 3x for f\left(x\right) in above equation to obtain \left( {g \circ f} \right)\left( x \right).

\begin{gathered}\left( {g \circ f}\right)\left( x \right)= g\left( {3x} \right) \\=\frac{1}{3}\left( {3x}\right)\\=x \\ \end{gathered}

Here, \left( {g \circ f} \right)\left( x \right) is equal to x and \left( {f \circ g} \right)\left( x \right) is equal to x.

Option A is not correct as 3x\left( {\dfrac{x}{3}} \right) is equal to {x^2} which is not equal to inverse x.

Option B is not correct as \left( {\dfrac{1}{3}x} \right)\left( {3x} \right) is equal to {x^2} which is not equal to inverse x.

\fbox{Option C} is correct as \dfrac{1}{3}\left( {3x} \right) is equal to x an it is equal to inverse x.

Option D is not correct as \frac{1}{3}\left( {\frac{1}{3}x} \right) is equal to \frac{1}{9}x which is not equal to inverse x.

Learn more:

1. Learn more about functions brainly.com/question/2142762

2. Learn more about range of the functions brainly.com/question/3412497

3. Learn more about relation and function brainly.com/question/1691598

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Functions

Keywords: functions, range, domain, inverse, reverse, fraction, relation, expression, \left( {g \circ f} \right)\left( x \right), \left( {f \circ g} \right)\left( x \right).

Andrew [12]3 years ago
4 0
If we want to verify that g ( x ) is the inverse of f ( x ) we have to show that:
( f ° g ) = ( g ° f )
f ( g ( x ) )=  3 · ( 1/3 x ) = x
g ( f ( x ) ) = 1/3 · ( 3 x ) = x
Answer:
C ) 1/3 ( 3 x )
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This is a lot easier to figure out if you simplify the fractions and then change them to decimals

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When you are ordering negatives, the biggest negative is the least. That is why -9/4 (-2.25) is the least number out of the five given.

The next one would be -0.75, because it is the second biggest negative fraction.

The next one is -0.60 because that is the 3rd biggest negative fraction (or the smallest because this is the last negative)

Now, because we're in the positives we start with 1.67, because it is smaller than the other number.

2.1 is our last number, so it is the greatest!

I hope this helped :)

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Step-by-step explanation:

To multiply decimals, begin by multiplying the numbers as if there is <u>no decimal</u>:

\large\begin{array}{cccccc}&& 1 & 2 & 8 & 5\\\times && & 3 &2 & 4\\\cline{1-6} && 5 & 1 & 4 & 0\\&2&5&7&0&0\\3&8&5&5&0&0\\\cline{1-6}4&1&6&3&4&0\\\cline{1-6}^1&^1&^1&&\phantom{^{\frac{1}{2}}}&\end{array}

Count the number of digits <u>after</u> the decimal point in each factor:

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