Answer:
secound one good luck
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
and 
lies between
and for this 
,
and 
is Positive as they lie in 2 nd Quadrant
Answer: 36.9
Step-by-step explanation:
For this question you have to find out whether you are using Sin, Cos or Tan.
To work out which one you are using you can use SOH CAH TOA to help you.
SOH- The 'S' is for Sin, the 'O' and the 'H' is for Opposite over Hypotenuse.
CAH- The 'C' is for Cos and the 'A' and the 'H' is for Adjacent over Hypotenuse.
TOA- The 'T' is for Tan, the 'O' and the 'A is for Opposite over Adjacent.
As you have the Opposite (the side opposite the angle we're looking for) and the Adjacent (the side next to the angle were looking for) we would be using Tan.
So first you would have to write:
Tanθ=3/4
Then because we want Theta (θ) on it's own we would have to do the inverse to 'undo' the equation. Tan-1 is the inverse of Tan.
θ=Tan-1 3/4
To find the answer you would have to put it in your calculator.
θ=36.9
Hope this helps :)
Answer:
<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>
Step-by-step explanation:
Let's recall that for solving a SSS triangle, we :
1. Use the Law of Cosines first to calculate one of the angles
2. Use The Law of Cosines again to find another angle
3. Finally use angles of a triangle add to 180° to find the last angle.
1. Cos x = (9² + 15² - 8.3²/2 * 9 * 15)
Cos x = (81 + 225 - 68.89/270)
Cos x = 0.878
x = Cos ⁻¹ (0.878)
x = 28.6° (rounding to the next tenth)
2. Cos y = (8.3² + 15² - 9²/2 * 8.3 * 15)
Cos y = (68.89 + 225 - 81/249)
Cos y = 0.855
x = Cos ⁻¹ (0.855)
x = 31.2° (rounding to the next tenth)
3. z = 180 - 31.2 - 28.6
z = 120.2°
<u>The correct answer is B. ∠X = 28.6°, ∠Y = 31.2°, ∠Z = 120.2°</u>
