Answer:
No its short 207
Step-by-step explanation:
Took the test on UsaTestPrep got it right :)
Bye loves <3
Answer:
When a line is parallel to another line, they have the same slope. So far the equation would be, y=4x+b. To find the value of b, substitute the given point into the equation.
8=4(-1)+b
8=-4+b
b=12
So, the equation of the line is y=4x+12.
:)
Answer:
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:

The statsitic would be given by:

Where O represent the observed values and E the expected values
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
If there was 20% taken off you add 20% back on and that is how you will get your answer. So take 760 plus the 20% which gives you 912 dollars
Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================




To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>

<u>apply chain rule</u>

<u>Equate the first derivative to zero, that is V'(x) = 0</u>




<u />
<u>maximum volume:</u> <u>when h = 40/3</u>


<u>minimum volume:</u> <u>when h = 0</u>

